- 3(x - y)(y - z)(z - x)
- 3(x - z)(y - x)(z - y)
- 3(x + y)(y + z)(z + x)
- 3(x + y)(y - z)(z + x)

Option 1 : 3(x - y)(y - z)(z - x)

**Given:**

The values of a, b and c is given

a = x - y

b - y - z

c = z - x

**Formula used:**

If a + b + c = 0

then, a3 + b3 + c3 = 3abc

**Calculations:**

According to the question, we have

If a = x - y, b = y - z and c = z - x

then, a + b + c will be

⇒ a + b + c = x - y + y - z + z - x

⇒ a + b + c = 0

So, The value of a3 + b3 + c3 = 3abc

⇒ a3 + b3 + c3 = 3(x - y)(y - z)(z - x)

**∴ The value of a3 + b3 + c3 is 3(x - y)(y - z)(z - x).**

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